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A subcritical accelerator-driven system loses beam power. The neutron population drops rapidly, but decay heat remains in the target and blanket. A reviewer asks why k-effective still matters if the system is subcritical. What is the best answer?
k-effective is irrelevant because only the accelerator beam creates neutrons
k-effective controls source multiplication and margin even though the system cannot sustain power without the source
k-effective applies only to commercial LWRs
Subcritical systems have no decay heat after beam trip
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